Question

How do you find the derivative of `((1+3x)/(3x))(3-x)`?

Answer 1

`-1 -1/x^2`

Explanation:

Combine the numerator by multiplying so that it is `(-3x^2+8x +3)/(3x)`

Now apply the quotient rule to differentiate or proceed as follows:

`(-3x^2+8x +3)/(3x)` =`-x +8/3 +1/x`

Now differentiate term wise = `-1 -1/x^2`