Question #4190b

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Answer 1 · 2017-01-27T04:41:06

#49x^2+42x-27=0#

for solution for #-9/7#
#x=-9/7#, then #(x+9/7)=0#

for solution 3/7,
#x=3/7#, then #(x-3/7)=0#

Therefore,
#(x+9/7)(x-3/7)=0#

#((7x+9)/7)((7x-3)/7)=0#

#(7x+9)(7x-3)=0#

#49x^2-21x+63x-27=0#

#49x^2+42x-27=0#

you also can use method #x^2-(SOR)x+POR=0#,

#x^2-(-9/7+3/7)x+(-9/7*3/7)=0#

#x^2-(-6/7)x-27/49=0#

#x^2+6/7x-27/49=0#

multiply by 49,

#49x^2+42x-27=0#