How do you solve #4x - 4( - 2x + 1) =4- 2( 4x + 24)#?

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Answer 1 · 2017-01-27T23:05:23

#x = -2#

#4x - 4(-2x + 1) = 4 - 2(4x + 24)#

#4x + 8x - 4 = 4 - 8x - 48#

#12x - 4 = -8x - 44#

#12x + 8x = -44 + 4#

#20x = -40#

Divide the both sides by 20

#(cancel(20)x)/cancel("20") = cancel(-"40")^-2/cancel("20")#

#x = -2#