How do you evaluate #2(6div3-1)*1/2#?

1 Answer
Jim G.
Jan 28, 2017

#1#

Explanation:

Follow the #color(blue)"order of operations"# as set out in the acronym PEMDAS.

[Parenthesis (brackets) , Exponents (powers) , Multiplication , Division , Addition and Subtraction ]

Contents of bracket must be evaluated first.

#rArr(6÷3-1)=(2-1)=1larrcolor(red)"bracket"#

Expression can now be written as.

#2xx1xx1/2#

#=cancel(2)^1xx1xx1/cancel(2)^1=1larrcolor(red)"multiplication"#

Related questions
See all questions in PEMDAS
Impact of this question
1240 views around the world
You can reuse this answer
Creative Commons License