How do you factor #15x²-17x+2#?

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Answer 1 · 2017-01-28T14:06:58

#15x^2-17x+2 = (x-1)(15x-2)#

Given:

#15x^2-17x+2#

Note that the sum of the coefficients is zero.

That is:

#15-17+2 = 0#

So we can deduce that #x=1# is a zero and #(x-1)# a factor.

In order to get the leading term #15x^2# and the constant term #2#, the other linear factor must be #(15x-2)#

So we have:

#15x^2-17x+2 = (x-1)(15x-2)#