How do you solve #[[e ^ { x } ( x ^ { 2} - 7x + 14) ] - 3= 0#?

1 Answer
Jan 28, 2017

#x=-2.545#, nearly. See graph for x-intercept

Explanation:

#y=e^x(x^2-7x+14)-3#

#y'=e^x((x^2-7x+14) + (2x-7)=e^x(x^2-5x+7)#

#=e^x(((x-5/2)^2+3/4)>0#

So, y is an increasing function, and so, the only solution is the x-

intercept in the graph, 2.5 nearly.

When y is an admixture of polynomial and exponential functions. the

solution is transcendental, and so, can be approximated to any

precision, by a suitable iterative numerical method, with 2.5 as the

starter. Root-bracketing method improves it to # 2.545#.

The second graph reveals crossing x-xis near# x= -2.545#, In this

graph, the scaling is nearly uniform.

graph{e^x(x^2-7x+14)-3 [-10, 10, -5, 5]}

graph{e^x(x^2-7x+14)-3 [-2.56, -2.53, -1.27, 1.27]}