How do you solve #P= \frac { b } { d + t }# for #t#?
2 Answers
Jan 28, 2017
Explanation:
-
Cross multiply
#P# and#d+t# to get:
#d+t# =# \frac {b} {P}# -
To make
#t# the subject, substract#d# (move#d# to the other
side!) :
#t# =#\frac {b} {P}# -#d#
Jan 28, 2017
Explanation:
We can
#color(blue)"cross multiply"# to 'eliminate' the fraction.We treat equations with letters only
#color(blue)"literal equations"# in exactly the same way as normal equations.
#rArrP/1=b/(d+t)#
#rArrP(d+t)=b# divide both sides by P
#(cancel(P) (d+t))/cancel(P)=b/P#
#rArrd+t=b/P# To solve for t, subtract d from both sides.
#cancel(d)cancel(-d)+t=b/P-d#
#rArrt=b/P-d" is the solution"#