How do you solve P= \frac { b } { d + t }P=bd+t for tt?

2 Answers
Jan 28, 2017

t = \frac {b} {p}t=bp - dd

Explanation:

  1. Cross multiply PP and d+td+t to get:
    d+td+t = \frac {b} {P}bP

  2. To make tt the subject, substract dd (move dd to the other
    side!) :
    tt = \frac {b} {P}bP - dd

Jan 28, 2017

t=b/P-dt=bPd

Explanation:

We can color(blue)"cross multiply"cross multiply to 'eliminate' the fraction.

We treat equations with letters only color(blue)"literal equations"literal equations in exactly the same way as normal equations.

rArrP/1=b/(d+t)P1=bd+t

rArrP(d+t)=bP(d+t)=b

divide both sides by P

(cancel(P) (d+t))/cancel(P)=b/P

rArrd+t=b/P

To solve for t, subtract d from both sides.

cancel(d)cancel(-d)+t=b/P-d

rArrt=b/P-d" is the solution"