How do you solve P= \frac { b } { d + t }P=bd+t for tt?
2 Answers
Jan 28, 2017
Explanation:
-
Cross multiply
PP andd+td+t to get:
d+td+t =\frac {b} {P}bP -
To make
tt the subject, substractdd (movedd to the other
side!) :
tt =\frac {b} {P}bP -dd
Jan 28, 2017
Explanation:
We can
color(blue)"cross multiply"cross multiply to 'eliminate' the fraction.We treat equations with letters only
color(blue)"literal equations"literal equations in exactly the same way as normal equations.
rArrP/1=b/(d+t)⇒P1=bd+t
rArrP(d+t)=b⇒P(d+t)=b divide both sides by P
(cancel(P) (d+t))/cancel(P)=b/P
rArrd+t=b/P To solve for t, subtract d from both sides.
cancel(d)cancel(-d)+t=b/P-d
rArrt=b/P-d" is the solution"