Question

Question #c4606

Answer 1

`"24 L"`

Explanation:

NIST uses a temperature of `20^@"C"` `("293.15 K"`, `68^@"F")` and an absolute pressure of `"1 atm"` `("14.696 psi"`, `"101.325 kPa")`. This standard is also called normal temperature and pressure (abbreviated as NTP).

Normal Temperature and Pressure

`"T = 293.15K"`
`P = 1 atm`

so

The only difference between STP and NTP is that NTP conditions are at `20^@"C" = "293.15 K"`, rather than at `0^@"C" = "273.15 K"`.

Since only the temperature is different, use Charle's Law:

`V_1/T_1 = V_2/T_2`

We have:

`V_1 = 22.41 L`

`T_1 = 273.15 K`

`V_2 = ? larr "This is the volume of 1 mol of a gas at NTP "`

`T_2 = 293.15 K.`

Plugging our information into Charle's Law:

`V_1/T_1 = V_2/T_2`

`=> (22.41 L)/(273.15 K) = V_2/(293.15 K)`

`=> V_2 = (22.41 L)(293.15 K)/(273.15 K) = 24.05 L`

`"Therefore, 1 mol of any gas will occupy about 24 L at NTP."`

Hope this helped