Question

How do you find the exact value of `2secx=2+secx` in the interval `0<=x<360`?

Answer 1

Solution : In interval `0 <= x <= 360 , x = 30^0 or x= 300^0`

Explanation:

`2 secx = 2 +sec x or 2 secx -sec x =2 or sec x =2 or 1/cosx=2 or cosx =1/2 ; cos 60 =1/2 and cos (360-60) =1/2 :. x = 30^0 or x= 300^0`

Solution : In interval `0 <= x <= 360 , x = 30^0 or x= 300^0`[Ans]