What is the probability of rolling a sum of 11 with two dice?

2 Answers

#2/36=1/18#

Explanation:

I'm assuming we're using standard fair 6-sided dice.

There are a total of #6xx6=36# possible rolls.

There are two ways to roll an 11: #(5, 6), (6, 5)#

And so the odds of rolling an 11 are:

#2/36=1/18#

Jan 30, 2017

#1/18#.

Explanation:

The Sample Space #S# for the Experiment is,

#S={(x,y) | 1 le x,y le 6} sub NNxxNN.#

#:." the No. of Elements in "S, i.e., n(S)=36#.

If #E"=the Event that Sum of the Nos. on the Dice is "11,#

# E={(5,6),(6,5)} rArr n(E)=2.#

Hence, the Reqd. Prob.#=P(E)=(n(E))/(n(S))=2/36=1/18.#