How do you write #-5-11x>5-7x# in interval notation?

1 Answer
MrsRudolph221
Jan 30, 2017

First, you must solve: #-5 - 11x > 5 - 7x#

Explanation:

Add 7x to both sides: #-5 + 7x - 11x > 5 - 7x + 7x#
Add 5 to both sides: #5 + -5 - 4x > 5 + 5 #
Simplify: #-4x > 10# , then divide by -4 and switch the inequality symbol.
#((-4x)/-4)<(10/-4)#
#x < -5/2#

Now, you should write your answer in interval notation, as follows: #(-oo,-5/2)# which represents all real numbers from #-oo# up to but not including #-5/2#.

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