Question

How do you graph the polar equation `r=3sec(theta+pi/3)`?

Answer 1

See graph. I have used the Cartesian form `x-sqrt3y-6=0`, instead.

Explanation:

`rcos(theta+pi/3)=(rcostheta)cos(pi/3)-rsinthetasin(pi/3)`

`=1/2(x-sqrt3y)=3`

graph{x-sqrt3y-6=0 [-10, 10, -5, 5]}