Question

How do you simplify `[(x^2+2x)(x^2+2x-3)]/[(x^2+x-2)(x^2+3x)]`?

Answer 1

1

Explanation:

Since

`x^2+2x=x(x+2)`
`x^2+2x-3=(x+3)(x-1)`
`x^2+x-2=(x+2)(x-1)`
`x^2+3x=x(x+3)`

you would substitute in the given fraction and symplify:

`((x^2+2x)(x^2+2x-3))/((x^2+x-2)(x^2+3x))=(x(x+2)(x+3)(x-1))/((x+2)(x-1)x(x+3))=1`