Question

Question #e55db

Answer 1

`- (3sqrt7)/8`

Explanation:

`sin t = 1/8.`
Find cos t by using trig identity:
`cos^2 t = 1 - sin^2 t`
`cos^2 t = 1 - 1/64 = 63/64`
`cos t = +- (3sqrt7)/8`
Since t is in Quadrant II, then cos t is negative
`cos t = - (3sqrt7)/8`