What is the area of a parallelogram with corners in #(-2,-1), (-12,-4), (9,-4), (-1,-7)#?

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Answer 1 · 2017-02-01T08:53:23

Area of parallelogram is #63#

This is a parallelogram with points as

#A(-2,-1), B(-12,-4), C(-1,-7), D(9,-4)#

and #AB#||#DC# and #AD#||#BC#

Area of #DeltaABC# is

#1/2((-2)(-4-(-7)+(-12)(-7-(-1))+(-1)(-1-(-4)))#

= #1/2((-2)xx3+(-12)xx(-6)+(-1)xx3)#

= #1/2(-6+72-3)=1/2xx63#

Hence area of parallelogram is #63#