How do you find the x and y intercepts of #4y=16#?

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Answer 1 · 2017-02-01T11:33:14

See the entire solution process below:

First, solve this equation for #y#:

#(4y)/color(red)(4) = 16/color(red)(4)#

#(color(red)(cancel(color(black)(4)))y)/cancel(color(red)(4)) = 4#

#y = 4#

Because there is no #x# term we know this is a horizontal line where for every value of #x# #y# is equal to #4#.

Therefore, the y-intercept is #4# or #(0, 4)#

Also, because this is a horizontal line there is no x-intercept.