Question

What is the maximum value of `f(x)=-3(x+3)^2+8`?

Answer 1

`f_(max) =8.`

Explanation:

`AA x in RR, (x+3)^2>=0`

Multiplying by #-3<0 will reverse the inequality.

`:. -3(x+3)^2<=0`.

Adding `8, -3(x+3)^2+8<=0+8`

`rArr f(x)<=8`

`:." The Reqd. Max. Value of f(x) is "8`.