How do you solve #3,330= 45( p + 35)#?

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Answer 1 · 2017-02-02T14:48:54

See the entire solution process below:

First, expand the terms in parenthesis on the right side of the equation:

#3330 = (45 xx p) + (45 xx 35)#

#3330 = 45p + 1575#

Next, subtract #color(red)(1575)# from each side of the equation to isolate the #p# term while keeping the equation balanced:

#3330 - color(red)(1575) = 45p + 1575 - color(red)(1575)#

#1755 = 45p + 0#

#1755 = 45p#

Now, divide each side of the equation by #color(red)(45)# to solve for #p# while keeping the equation balanced:

#1755/color(red)(45) = (45p)/color(red)(45)#

#39 = (color(red)(cancel(color(black)(45)))p)/cancel(color(red)(45))#

#39 = p#

#p = 39#