How do you find the formula units in 2.6 g of lithium bromide?

1 Answer
Feb 2, 2017

"Number of formula units of LiBr"Number of formula units of LiBr ~= 2xx10^222×1022

Explanation:

"Number of formula units of LiBr"="Mass"/"Molar mass of LiBr"xxN_ANumber of formula units of LiBr=MassMolar mass of LiBr×NA

where N_A="Avogadro's number"-=6.022xx10^23*mol^-1NA=Avogadro's number6.022×1023mol1

And thus, (2.6*cancelg)/(86.84*cancelg*cancel(mol^-1))xx6.022xx10^23*cancel(mol^-1)=??

Since all the units cancel out, we get the answer as a number, as required.