Question

How do you add `\frac { 12y } { y ^ { 2} + 16y + 48} + \frac { 6} { y + 4}`?

Answer 1

`(6(y+14))/((y+4)(y+12))`

Explanation:

`12/(y^2+16y+48)+6/(y+4)`
Factorise
`12/((y+4)(y+12))+6/(y+4)`

So to get a common denominator multiply numerator and denominator of the second term by y+12

`=12/((y+4)(y+12))+6/(y+4)*(y+12)/(y+12)`

`=(12+6(y+12))/((y+4)(y+12))`
`=(12+6y+72)/((y+4)(y+12))`
`=(6y+84)/((y+4)(y+12))`
`=(6(y+14))/((y+4)(y+12))`