How do you solve #33,000+ 0.013s \geq 94,100#?

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Answer 1 · 2017-02-02T23:34:41

See the entire solution process below:

First, subtract #color(red)(33000)# from each side of the inequality to isolate the #s# term while keeping the inequality balanced:

#33000 - color(red)(33000) + 0.013s >= 94100 - color(red)(33000)#

#0 + 0.013s >= 61100#

#0.013s >= 61100#

Now, divide each side of the inequality by #color(red)(0.013)# to solve for #s# while keeping the inequality balanced:

#(0.013s)/color(red)(0.013) >= 61100/color(red)(0.013)#

#(color(red)(cancel(color(black)(0.013)))s)/cancel(color(red)(0.013)) >= 4700000#

#s >= 4,700,000#