Question

Question #b576d

Answer 1

The depression of freezing point of solvent `DeltaT_f` is related with the molality `m` of the solute as follows

`color(blue)(DeltaT_f=-i*K_f*m..........[1])`

where

`K_f->"cryoscopic constant "=1.853Kkg"/mol for water"`

`m->"molality of the soute"=0.100`

`i->" van't hoff factor"=1+alpha`

`alpha->"degree of dissociation"=1.32%=0.0132`

Replacing i by `1+alpha` the equation [1] becomes

`color(green)(DeltaT_f=-(1+alpha)*K_f*m)`

`color(green)(=>DeltaT_f=-(1+1.0132)*1.853*0.1K~~-0.188K)`

So expected freezing point will be

`color(red)("Expected freezing point"=(273-0.188)K=272.812K)`