How do you simplify #(4x^2)/(2x^(1/2))#?

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Answer 1 · 2017-02-05T07:46:41

#2x^(3/2)#

Start with

#(4x^2)/(2x^(1/2)#

I'm going to first break this down so that we have constants in one fraction and #x# terms in the other:

#(4/2)(x^2/x^(1/2))#

Let's do #4/2# first - it's #4/2=2#

Now let's do the #x# terms. We can use #x^a -: x^b=x^(a-b)# to write our fraction as:

#x^2 -: x^(1/2)=x^(2-1/2)=x^(3/2)#

Putting it all together, we get:

#2x^(3/2)#