How do you solve #\frac { g + 12} { 3} \leq 6#?

Question

438 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-02-05T22:46:59

See the entire solution process below:

First, multiply each side of the inequality by #color(red)(3)# to eliminate the fraction while keeping the inequality balanced:

#color(red)(3) xx (g + 12)/3 <= color(red)(3) xx 6#

#cancel(color(red)(3)) xx (g + 12)/color(red)(cancel(color(black)(3))) <= 18#

#g + 12 <= 18#

Now, subtract #color(red)(12)# from each side of the inequality to solve for #g# while keeping the inequality balanced:

#g + 12 - color(red)(12) <= 18 - color(red)(12)#

#g + 0 <= 6#

#g <= 6#