Question

Question #7b152

Answer 1

In the ORS ratio of

`" salt ":"glucose"=1:12`

So the percentage of salt in the mixture
`=1/13xx100%`

In the salt (`NaCl`) the ratio of `(Cl):(Na)=35.5:23`
So the fraction of (Cl) in the salt is`=35.5/(35.6+23)=35.5/58.5`

So the percentage of `Cl` in the mixture
`=35.5/58.5xx1/13xx100%~~4.66%`