How do you evaluate #2\times ( 3x + 4) ^ { 2}#?

1 Answer
jess_r
Feb 7, 2017

18#x^2# + 48#x# + 32

Explanation:

Use the double distributive property (also known as the FOIL method) to first solve #(3#x# + 4)^2#. So, multiply 3x by 3x, multiply 3x by 4, multiply 4 by 3x, multiply 4 by 4, then add it all together, resulting in 9#x^2# + 24#x# + 16. Lastly, multiply each number by 2, which will give you 18#x^2# + 48#x# + 32.

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