How do you factor #2x^2 + x - 3 =0#?
1 Answer
Feb 7, 2017
Explanation:
Given:
#2x^2+x-3 = 0#
Note that the sum of the coefficients is
#2+1-3 = 0#
Hence
#0 = 2x^2+x-3 = (x-1)(2x+3)#