Question

What is the volume of a container that holds 9.67 moles of oxygen gas at 100°C and 1.30 atm pressure?

Answer 1

`V=(nRT)/P~=228*L`

Explanation:

`V=(9.67*molxx0.0821(L*atm)/(K*mol)xx373K)/(1.30*atm)`.

What is the mass of the oxygen gas?