Question

How do you find the indefinite integral of `int cost/(1+sint)`?

Answer 1

`ln|sint + t| + C`

Explanation:

Let `u = sint + 1`. Then `du = cos t dt` and `dt = (du)/cost`.

`=>int cost/u * (du)/cost`

`=>int 1/u du`

`=>ln|u| + C`

`=>ln|sint + t| + C`

Hopefully this helps!