What is the vapor pressure of water at 105°C?

1 Answer

You can do this with the Antoine equation:

#log P = A - B/(C+T)#

where:

  • #P# is the vapor pressure of water.
  • #T# is the water temperature in celsius.
  • #A,B,# and #C# are the Antoine constants for water.

When the water temperature is in the range of #1 - 100^@ "C"#:

#A=8.07131, B=1730.63, C= 233.426#

When the water temperature is in the range of #99-374^@ "C"#:

#A=8.14019, B=1810.94, C=244.485#

If you calculate using this way you will get answer in #"torr"#:

#P = 10^(A - B/(C+T))#

#= 10^{8.14019-{1810.94}/{105+244.485}}#

#= 10^{8.14019-5.18174}#

#= 10^{2.95845}#

#=# #"908.76 torr"#

This is the water pressure at #105^@ "C"#.