Question

How do you solve `6( t - 3) = 2( 9k-2t )`?

Answer 1

`k = 5/9t - 1` or `t = 9/5k + 9/5`

Explanation:

`6(t-3) = 2(9k-2t)`
`3(t-3) = 9k - 2`
`3t - 9 = 9k - 2t`
`5t - 9 = 9k`

Therefore:
`k = 5/9t - 1` or `t = 9/5k + 9/5`