Question

How do you solve `2x^2+9x-18=0`?

Answer 1

`x = 3/2` or `x = -6`

Explanation:

`2x^2+9x-18=0`

use the ABC Formula, where you use:
`x = (-b ± sqrt(b^2 - 4ac))/(2a)`
with:
`a=2`
`b=9`
`c=-18`

so when you fill that in:

`x = (-9 + sqrt(9^2 - (4*2*-18)))/(4) = 3/2`
or
`x = (-9 - sqrt(9^2 - (4*2*-18)))/(4) = -6`