Question

In the limit `lim (x^2-4x)/(2x)=-2` as `x->4`, how do you find `delta>0` such that whenever `0<abs(x)<delta`, `abs((x^2-4x)/(2x)-(-2))<0.01`?

Answer 1

Check this question, as:

`lim_(x->4) (x^2-4x)/(2x) = 0`