How do you solve #sqrt(2x+1)+sqrt(2x+6)=5#?
1 Answer
Feb 9, 2017
x= 3/2
Explanation:
- Try move one square to the other side:
#sqrt(2x+1)=5-sqrt(2x+6)# - Take a square and you will get:
#2x+1=25+2x+6-10*sqrt(2x+6)# - And now the 2xs are cancelled on both sides, rearrange and you will get:
#10*sqrt(2x+6)=30# - Now the equation is simple, take a square on both sides and you will get the answer.
