Question

Question #2b1f4

Answer 1

`2.0xx10^3" Pa"`

Explanation:

As shown in the figure bottom face of the sample is held rigidly bound and a shearing/tangential force `F` is applied on upper face of area `A`. The modulus of rigidity `G` is defined as the ratio of shear stress to the shear strain.

Shear stress`=F/A` and
shear strain `=tan theta=(Deltax)/l`
`Delta x` is the transverse displacement of the area on which force is acting and `l` is the initial length of the side.

`G -= "Shear stress"/"Shear strain"= (F / A)/ ((Δ x) / l)`
`=>G= (F l)/( A Δ x)" Pa"`

Inserting given values in SI units we get

`G= 10 xx(10/100)/( 0.05/100)`
`=>G= 10 xx(10)/( 0.05)`
`=>G=2.0xx10^3" Pa"`