How do you solve #3x^2+5=5x^2+10#?

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Answer 1 · 2017-02-10T18:52:13

#x=+isqrt(5/2)# and #x=-isqrt(5/2)#

Although this is under the section "completing the square," that is not what is required to solve this problem.

Step 1. Move everything to the left hand side

#3x^2-5x^2+5-10=0#

Step 2. Combine like terms

#-2x^2-5=0#

Step 3. Solve for #x#

#-2x^2-5=0#
#-2x^2=5#
#x^2=-5/2#
#x=+-isqrt(5/2)#