A 0.016 kg silver bracelet has a volume of 9.27 #cm^3#. What is its density?

1 Answer
anor277
Feb 11, 2017

#rho~=1.7*g*cm^-3#

Explanation:

#"Density"# #=# #"Mass"/"Volume"# #=# #(0.016*kgxx10^3*g*kg^-1)/(9.27*cm^3)#

#=1.73*g*cm^-3#

Now chemists would usually use density values of #g*mL^-1# or #g*cm^-3#. These can be converted into #kg*m^-3#, but these large values are inutile.

Note that I just looked over this question, and the calculated density is ABSURDLY low. So I would review your source. A typical value for silver metal would be #rho=10.5*g*cm^-3#.

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