Question

Question #2fa3d

Answer 1

`(− sec ( x ) tan^2 ( x ) − ( 9 − sec ( x ) ) sec^2 ( x ))/tan^2 x`

`=(− sec ( x ) (sec^2 ( x ) -1)− ( 9 − sec ( x ) ) sec^2 ( x ))/tan^2 x`

`=(− sec^3 ( x )+ secx− 9sec^2x + sec^3 ( x ))/tan^2 x`

`=(secx− 9sec^2x )/tan^2 x`

`=secx/tan^2x− (9sec^2x)/tan^2 x`

`=cosx xxcsc^2x− 9csc^2x`