Question

How do you differentiate `f(x)=tanx/(cosx-4)`?

Answer 1

`f'(x)=(sec^2x(cosx-4)+sinxtanx)/(cosx-4)^2`

Explanation:

Using the quotient rule, we get:

`f'(x)=(sec^2x(cosx-4)+sinxtanx)/(cosx-4)^2`