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Answer 1 · 2017-02-13T18:10:38

0.095 cms /sec

Let volume of water in the cylindrical tank be V litres, when water has an height of 'h' metres. Volume of water would be #pi h # cubic metres

V= #1000 pi h# (because 1 cubic metre equal 1000 litres)

Differentiating both sides, it would be

#(dV)/dt= 3= 1000 pi (dh)/dt#

Rate of change of height #(dh)/dt=3/(1000pi)#= 0.000955 m/s=0.095 cms/s