Question

How do you expand `ln(8^5/7)^4`?

Answer 1

`ln(8^5/7)^4=20ln8-4ln7`

Explanation:

We can use the identities `lna^b=blna` and `ln(a/b)=lna-lnb`

Hence `ln(8^5/7)^4`

= `4ln(8^5/7)`

= `4(ln8^5-ln7)`

= `4(5ln8-ln7)`

= `20ln8-4ln7`