Question

How do you solve `4x^2>12x-9`?

Answer 1

The answer is `x in RR-{3/2}`

Explanation:

Let's rearrange and factorise the inequality

`4x^2>12x+9`

`4x^2-12x+9>0`

`(2x-3)(2x-3)>0`

`(2x-3)^2>0`

Let `f(x)=(2x-3)^2`

Therefore,

`f(x)>0 ; AA x in RR-{3/2}`