Question #21b57

1 Answer
Feb 15, 2017

Well, find me a transition metal that has four unpaired electrons in its five #(n-1)d# orbitals.


Did you choose tungsten (#"W"#)? If so, good choice, because its electron configuration for the valence electrons is #4f^14 color(blue)(5d^4) 6s^2#.

(If you picked #"Cr"# or #"Mo"#, then you should review their electron configurations. They have #5# unpaired #(n-1)d# electrons, and are notorious "exceptions" to so-called expected orbital filling orders.)

Verify that #"W"# is an atom and that it is neutral.