Question

Question #0c37e

Answer 1

Given

`"Total pressure of moisture and He "P=1.20atm`

`"Partial pressure of sat.vapour at" 45^@C=(f)=71.88"torr"=71.88/760atm~~0.095atm`

`"Temperature "T=(45+273)=328K`

`"Pressure of He"=p_(He)=1.20-0.95=1.105atm`

`"Mass of He"=0.586g`

`n_(He)=(0.586g)/(4g"/mol")=0.1465mol`

Now by ideal gas equation

`p_(He)V_(He)=n_(He)RT`

`V_(He)=(0.1465molxx0.082LatmK^-1mol^-1xx328K)/(1.105atm)`

`~~3.57L`