How do you find the product (y-2)(y+4)?

1 Answer
Feb 15, 2017

color(blue)(y² + 2y -8)

Explanation:

using the Distributive Property of Real Numbers,
FOIL METHOD (First Term, Outer Term, Inner Term, and the Last Term)

color(blue)((a+b)(a+b) = a² + 2ab + b²)
color(blue)((a-b)(a+b) = a² - b²)

Answering using the Distributive Property color(red)((FOIL))
= (y−2)(y+4)
First Term,
= (color(blue)(y − 2)(color(blue)(y)+4)
Outer Term,
= (color(blue)(y − 2)(y+color(blue)(4))
Inner Term,
= (ycolor(blue)(−2))(color(blue)(y)+4)
Last Term,
=(ycolor(blue)(-2))(ycolor(blue)(+4))

First Term, y and y
= y * y = color(blue)(y²)

Outer Term, y and 4
= y * 4 = color(blue)(4y)

Inner Term, -2 and y
= -2 * y = color(blue)( -2y)

Last Term, -2 and +4
= -2 * 4 = color(blue)(-8)

Plugging all the answers, we get:

= color(blue)(y² + 4y - 2y -8)

always simplify the answer by combining (adding) like terms, the like term is the 4y and -2y, we get 4y + (-2y) = 2y

so the final answer is,

= color(blue)(y² + 2y -8)