How do you find the x and y intercepts of #2.5x-5y=-15#?

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Answer 1 · 2017-02-15T20:42:07

see the entire solution process below:

To find the y-intercept, set #x = 0# and solve for #y#:

#(2.5 xx 0) - 5y = -15#

#0 - 5y = -15#

#-5y = -15#

#(-5y)/color(red)(-5) = -15/color(red)(-5)#

#(color(red)(cancel(color(black)(-5)))y)/cancel(color(red)(-5)) = 3#

#y = 3#

The y-intercept is #3# or #(0, 3)#

To find the x-intercept, set #y = 0# and solve for #x#:

#2.5x - (5 xx 0) = -15#

#2.5x - 0 = -15#

#2.5x = -15#

#(2.5x)/color(red)(2.5) = -15/color(red)(2.5)#

#(color(red)(cancel(color(black)(2.5)))x)/cancel(color(red)(2.5)) = -6#

#x = -6#

The x-intercept is #-6# or #(-6, 0)#