A container with a volume of #18 L# contains a gas with a temperature of #250^o C#. If the temperature of the gas changes to #360 ^o K# without any change in pressure, what must the container's new volume be?

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Answer 1 · 2017-02-16T06:49:09

The new volume is #=12.39L#

We apply Charles' Law

#V_1/T_1=V_2/T_2#

#V_1=18L#

#T_1=250+273=523K#

#T_2=360K#

#V_2=T_2/T_1*V_1#

#=360/523*18=12.39L#