How do you solve #x^3 -3x^2 +16x -48 = 0#?
1 Answer
Feb 16, 2017
Explanation:
From sign changes in the coefficients, the equation has utmost 3
positive roots,There are no changes in sign,
when x is changed to
The cubic is 0 at x = 0. So, it becomes
The other solutions are from by
graph{(x-3)(x^2+16) [2, 4, -500, 500]} 0, -500, 500]}
Not to scale. It is large y vs small x, for approximating the solution.