Question

How do you simplify `(6a+18)/(9a+27)`?

Answer 1

Se the entire simplification process below:

Explanation:

First, factor the numerator and denominator as:

`(6a + 18)/(9a + 27) = (6(a + 3))/(9(a + 3)) = ((3 xx 2)(a + 3))/((3 xx 3)(a + 3))`

We can now cancel common terms in the numerator and denominator:

`((color(red)(cancel(color(black)(3))) xx 2)color(blue)(cancel(color(black)((a + 3)))))/((color(red)(cancel(color(black)(3))) xx 3)color(blue)(cancel(color(black)((a + 3))))) = 2/3`

However, because `9a + 27` cannot equal `0` the complete answer is:

`2/3` where `a != -3`